Calculate the slope of a line that intersects pounts (6,2) and (-4,-3)

Use the formula y-y/x-x, which is 2--3/6--4. This makes 2+3/6+4, which is 5/10, or 1/2, so the slope would be 1/2

Keep in mind that slope = "change in Y over change in X" and that the number pairs are written in the form of (x, y).

Slope = (y2 - y1) / (x2 - x1)

So:

Slope = (2 - (-3)) / (6 - (-4))

Slope = (2 + 3) / (6 + 4)

Slope = 5 / 10

Slope = 1/2, or 0.5

(simple algebra factoid: remember that when you subtract a negative number, the two "negatives" cancel out and you end up adding the two numbers: 6 - (-4) is the same as 6 + 4.

Good luck!