Solve by factoring 3x²-x-4=0

(3x + 1) (x - 1)

Step-by-step explanation:

The given fraction is three 'x' to the power of two that is minus from 'x' minus from four. Simplifying that into three 'x' to the power of two. After this three minus 'x' plus four 'x' minus four. By taking common values which is three 'x' multipled by 'x' and minus one adding the entire by the value four which is further multipled by 'x' and minus one. Finally we obtain our answer that is three 'x' plus one multipled the entire by 'x' and minus one.

3x^2-x-4

3x^2

-3x+4x - 4

Take common

3x (x - 1) + 4 (x - 1)

(3x + 1) (x - 1)