Suppose that a customer is purchasing a car. He conducts an experiment in which he puts 10 gallons of gas in the car and drives it until it runs out of gas. Be conducted this experiment 15 times on each car and records the number of miles driven.

Question Continuation:

Car 1, Car 2

227,240

209,237

237,212

229,227

209,251

261,159

251,208

251,260

282,169

250,269

254,296

254,312

271,307

259,287

262,277

What is the sample mean for car 1 and 2?

What is the median of car 1 and 2?

Answer:

Car 1

Mean = 247.067, Median = 251

Car 2

Mean = 247.4, Median = 251

Step-by-step explanation:

Given

N = Number of Observation = 15

Mean = Summation of Observation/N

For Car 1;

Mean = (227 + 209 + 237 + 229 + 209 + 261 + 251 + 251 + 282 + 250 + 254 + 254 + 271 + 259 + 262) / 15

Mean = 3706/15

Mean = 247.067

For Car 2;

Mean =

(240 + 237 + 212 + 227 + 251 + 159 + 208 + 260 + 169 + 269 + 296 + 312 + 307 + 287 + 277) / 15

Mean = 3711/15

Mean = 247.4

Calculating Median

For Car 1;

First, we arrange the numbers in ascending order;

209, 209, 227, 229, 237, 250, 251, 251, 254, 254, 259, 261, 262, 271, 282

The are odd number of observations.

Median = 15/2 = 8th position.

The observation at the 8th position is 251

For Car 2

159, 169, 208, 212, 227, 237, 240, 251, 260, 269, 277, 287 296, 307, 312

The are odd number of observations.

Median = 15/2 = 8th position.

The observation at the 8th position is 251