8. Calculate the area of rectangle A, the area of rectangle

B, and the area of the largest rectangle.

Then, using a fraction, compare the area of rectangle A

with the area of the largest rectangle. In other words,

the area of rectangle A is what fraction of the area of the

largest rectangle? Express this fraction in lowest terms.

2x on the side and the bottom of rectangle A and 2x on the side of rectangle B and x on the top.

Question

Winston Lucero

Mathematics

9 October, 10:44

8. Calculate the area of rectangle A, the area of rectangle

B, and the area of the largest rectangle.

Then, using a fraction, compare the area of rectangle A

with the area of the largest rectangle. In other words,

the area of rectangle A is what fraction of the area of the

largest rectangle? Express this fraction in lowest terms.

2x on the side and the bottom of rectangle A and 2x on the side of rectangle B and x on the top.

+3

Answers (2)

Know the Answer?

Evie Boyd · Answer 1

A: 4x^2 B: 2x^2 largest: 4x^2 fraction: 1

Step-by-step explanation:

a) The area of a rectangle is the product of length and width:

areaA = (2x) (2x) = 4x^2

b) areaB = (2x) (x) = 2x^2

c) The area of the largest rectangle is areaA = 4x^2

d) The ratio of areaA to the largest rectangle is ...

(4x^2) / (4x^2) = 1

Area A is 1 of the area of the largest rectangle.

Kristin Garcia · Answer 2

A: 4x^2

B: 2x^2

largest: 4x^2

fraction: 1

Step-by-step explanation:

a) The area of a rectangle is the product of length and width:

areaA = (2x) (2x) = 4x^2

b) areaB = (2x) (x) = 2x^2

c) The area of the largest rectangle is areaA = 4x^2

d) The ratio of areaA to the largest rectangle is ...

(4x^2) / (4x^2) = 1

Area A is 1 of the area of the largest rectangle.