What is the solution set of 2x^2 - 3x = 5?

{-1, - 5/2}

{-1, 5/2}

{1, - 5/2}

Question

Guest

Mathematics

15 September, 04:56

What is the solution set of 2x^2 - 3x = 5?

{-1, - 5/2}

{-1, 5/2}

{1, - 5/2}

+1

Answers (2)

Know the Answer?

Terrance · Answer 1

Terrance 15 September, 05:05

0

The answer is x = {-1, 2.5}

Cassius Mcintyre · Answer 2

The answer is {-1, 5/2} and heres why:

The first step to solveing this equation is to set it to 0 like this Subtract 5 from both sides: 2x^2 - 3x - 5 = 5 - 5 then just Simplify: 2x^2 - 3x - 5 = 0

Now to solve we must use a certain quadratic eqaution shown down below, because i have no other way to show my math better.

Now replace a with 2, b with - 3, and c with - 5. You then have to solve both for the postive equation and the negative equation.

If you would like even more detail just ask in the comments!

What is the solution set of 2x^2 - 3x = 5?{-1, - 5/2}{-1, 5/2}{1, - 5/2}

What is the solution set of 2x^2 - 3x = 5?

{-1, - 5/2}

{-1, 5/2}

{1, - 5/2}