A horse race has 13 entries and one person owns 5 of those horses. assuming that there are no ties, what is the probability that those five horses finish first, second, third, fourth, and fifth (regardless of order) ? the probability first, second, third, fourth, and fifth is nothing.

Question

Reagan Riley

Mathematics

7 March, 11:12

A horse race has 13 entries and one person owns 5 of those horses. assuming that there are no ties, what is the probability that those five horses finish first, second, third, fourth, and fifth (regardless of order) ? the probability first, second, third, fourth, and fifth is nothing.

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Asa Holt · Answer 1

There are 13 entries in total

The owner has 5 horses.

If each horses has the same probability of winning, then the probability that the owners

Horses will come in first, second, third, and fourth will be as follows:

It was only specified that one of these horses needed to be in each position

This makes it is a combination type problem because order does not matter

We 5 horses

The probability that one of those 5 horses will be first is 5/13

The probability that one of those remaining 4 horses will be second is 4/12

The probability that one of those remaining 3 horses will be third is 3/11

The probability that one of those remaining 2 horses will be fourth is 2/10

The probability that one of those remaining 1 horses will be fifth is 5/9

The total probability is that 0.00389