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14 January, 12:37

Eight more than twice a number increased by 3 is equal to 79. Find the number

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  1. 14 January, 12:42
    0
    translate, call the number, n

    Eight more than (8+) twice a number increased by 3 (2 (n+3)) is equal to (=) 79 (79)

    8+2 (n+3) = 79

    minus 8 both sides

    2 (n+3) = 71

    divide both sides by 2

    n+3=35.5

    minus 3 both sides

    n=32.5

    the number is 32.5
  2. 14 January, 12:48
    0
    This problem can be interpreted different ways.

    Here's how I interpret it:

    Eight more than twice a number, increased by 3, is equal to 79. Find the number

    Let n = the number

    "Eight more": + 8

    "Eight more than twice a number": 2n + 8

    "Eight more than twice a number increased by 3": 2n + 8 + 3

    "Eight more than twice a number increased by 3 is equal to 79.":

    2n + 8 + 3 = 79

    Now we solve the equation for n.

    2n + 8 + 3 = 79

    2n + 11 = 79

    2n = 68

    n = 34

    The number is 34.
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