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6 June, 08:15

On two investments totaling $10,500, Brian lost 6% on one and earned 8% on the other. If his net annual receipts were $497, how much was each investment?

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  1. 6 June, 08:26
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    Let

    x = the amount invested on the winner, then

    10500-x = amount invested on the losing investment.

    We know that the net profit is $497, so

    0.08x - 0.06 (10500-x) = 497

    Solve for x:

    0.14x = 497+630=1127

    x=1127/0.14=8050

    Therefore Brian invested $8050 on the investment that earned 8% and $2450 on the one that lost 6%.
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