Solve the system of equations algebraically 5x - 3y = 6 6x - 4y = 2

The system of equation will be solved as follows:

5x-3y=6 ... i

6x-4y=2 ... ii

to solve by elimination methods, we have:

multiplying the top equation by 6 and the bottom equation by 5 then subtract the top from the bottom we get:

-2y=-20

y=10

next we multiply eqn i be 4 and eqn ii be 3 then subtract i from ii we get:

4x=18

x=4.5

thus x=4.5 y=10