Which function has an asymptote at x=pi/2?

a) y = sec x

b) y = cot x

c) y = csc x

d) y = cos x

Question

Libby Stark

Mathematics

25 April, 02:26

Which function has an asymptote at x=pi/2?

a) y = sec x

b) y = cot x

c) y = csc x

d) y = cos x

+1

Answers (1)

Know the Answer?

Cantrell · Answer 1

Step-by-step explanation:

Note that y = sec x is the same as y = 1 / cos x, and that cos x is 0 at π/2. Division by zero is not defined. Thus, x cannot = π/2, and there is a vertical asymptote there.

Thus, the first answer choice, y = sec x, is the correct one.

Which function has an asymptote at x=pi/2?a) y = sec xb) y = cot xc) y = csc xd) y = cos x

Which function has an asymptote at x=pi/2?

a) y = sec x

b) y = cot x

c) y = csc x

d) y = cos x