Prove that (n+5) ^2 (n+3) ^2 is a multiply of 4

Solve for n:

(n + 3) ^2 (n + 5) ^2 = 0

Split into two equations:

(n + 3) ^2 = 0 or (n + 5) ^2 = 0

Take the square root of both sides:

n + 3 = 0 or (n + 5) ^2 = 0

Subtract 3 from both sides:

n = - 3 or (n + 5) ^2 = 0

Take the square root of both sides:

n = - 3 or n + 5 = 0

Subtract 5 from both sides:

Answer: n = - 3 or n = - 5 thus the Answer is wrong, neither - 3 or - 5 are a multiple of 4