Gerry is a restaurant manager and plans to advertise her restaurant. The advertising budget is $5000, and she plans to run television and online ads. She would like to run at least 5 television ads and 10 online ads. A television ad costs $500 and an online ad costs $150. Let x represent the number of television ads and y represent the number of online ads. Two of the constraints for this situation are x≥5 and y≥10. What is the other constraint for this situation?

Question

Matilda Rowe

Mathematics

7 August, 17:00

Gerry is a restaurant manager and plans to advertise her restaurant. The advertising budget is $5000, and she plans to run television and online ads. She would like to run at least 5 television ads and 10 online ads. A television ad costs $500 and an online ad costs $150. Let x represent the number of television ads and y represent the number of online ads. Two of the constraints for this situation are x≥5 and y≥10. What is the other constraint for this situation?

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Reagan Garrison · Answer 1

We are given the two constraints:

x ≥ 5 and y ≥ 10

Now the other constraint must of course be based on the sum of the two. It was given that the budget is $5000 so the sum must be greater than that, that is:

500 x + 150 y ≤ 5000