21 January, 05:18

What is the completely factored form of f (x) = x3-7x2+2x+4?

f (x) = (x-1) (x - (3+52--√)) (x - (3-52--√))

f (x) = (x+1) (x - (3+13--√)) (x - (3-13--√))

f (x) = (x+1) (x - (3+52--√)) (x - (3-52--√))

f (x) = (x-1) (x - (3+13--√)) (x - (3-13--√))

Answers (1)

Know the Answer?

Not Sure About the Answer?

Find an answer to your question 👍 “What is the completely factored form of f (x) = x3-7x2+2x+4? f (x) = (x-1) (x - (3+52--√)) (x - (3-52--√)) f (x) = (x+1) (x - (3+13--√)) (x ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.

Search for Other Answers

What is the completely factored form of f (x) = x3-7x2+2x+4?f (x) = (x-1) (x - (3+52--√)) (x - (3-52--√))f (x) = (x+1) (x - (3+13--√)) (x - (3-13--√))f (x) = (x+1) (x - (3+52--√)) (x - (3-52--√))f (x) = (x-1) (x - (3+13--√)) (x - (3-13--√))

What is the completely factored form of f (x) = x3-7x2+2x+4?

f (x) = (x-1) (x - (3+52--√)) (x - (3-52--√))

f (x) = (x+1) (x - (3+13--√)) (x - (3-13--√))

f (x) = (x+1) (x - (3+52--√)) (x - (3-52--√))

f (x) = (x-1) (x - (3+13--√)) (x - (3-13--√))