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21 January, 05:40

If u is inversely proportional to the square of v and u is 4/9 when v is 3, find u when v is 8

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  1. 21 January, 05:47
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    Answer:u=1/16

    Step-by-step explanation:

    u is inversely proportional to v^2

    u=k * 1/v^2

    u=k/v^2

    When U=4/9 when v=3

    4/9=k*1/3^2

    4/9=k*1/9

    4/9=k/9

    Cross multiply

    4*9=k*9

    36=9k

    Divide both sides by 9

    36/9=9k/9

    4=k

    When v = 8, u=?

    u=k/v^2

    Recall k=4

    u=4/8^2

    u=4/64

    u=1/16
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