Given that sin0=21/29 what is the value cos 0 for 0°< 0<90°

20/29

Step-by-step explanation:

sin θ = 21/29

Use Pythagorean identity:

sin² θ + cos² θ = 1

(21/29) ² + cos² θ = 1

441/841 + cos² θ = 1

cos² θ = 400/841

cos θ = ±20/29

Since 0° < θ 0. So cos θ = 20/29.