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12 August, 16:23

Consider the following intermediate chemical equations.

3 equations. 1: upper C upper H subscript 4 (g) right arrow upper C (s) plus 2 upper H subscript 2 (g). Delta H 1 equals 74.8 kilojoules. 2: upper C upper C l subscript 4 (g) right arrow upper C (s) plus 2 upper C l subscript 2 (g). Delta H 2 equals 95.7 kilojoules. Upper H subscript 2 (g) plus upper C l subscript 2 (g) right arrow 2 upper H upper C l (g). Delta H subscript 3 equals negative 92.3 kilojoules.

What is the enthalpy of the overall chemical reaction Upper C upper H subscript 4 (g) plus 4 upper C l subscript 2 (g) right arrow upper C upper C l subscript 4 (g) plus 4 upper H upper C l (g).?

-205.7 kJ

-113.4 kJ

-14.3 kJ

78.0 kJ

+3
Answers (1)
  1. 12 August, 16:41
    0
    A. - 205.7 kJ

    Step-by-step explanation:

    The overall enthalpy of reaction be calculated when the intermediate steps are present

    formed in a multi-step process.
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