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6 February, 23:57

What is the range of the function () = 12-2 f (x) = 1 2 x - 2 when the domain is {2, 4, 6}?

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  1. 7 February, 00:05
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    {-1, 0, 1}

    Step-by-step explanation:

    If your function is f (x) = 1/2x - 2, then the range is found by executing the function on each of the domain values:

    f (2) = 2/2 - 2 = - 1

    f (4) = 4/2 - 2 = 0

    f (6) = 6/2 - 2 = 1

    The range is {-1, 0, 1}.
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