Many urban zoos are looking at ways to effectively handle animal waste. One zoo has installed a facility that will transform animal waste into electricity. To estimate how many pounds of waste they may have to fuel the new facility they began keeping meticulous records. They discovered that the amount of animal waste they were disposing of daily is approximately Normal with a mean of 348.5 pounds and a standard deviation of 38.2 pounds. Amounts over 350 pounds would generate enough electricity to cover what is needed to for the entire aquarium that day. Approximately what proportion of the days can the zoo expect to obtain enough waste to cover what is needed to run the entire aquarium for the day?

(A) 0.484

(B) 0.499

(C) 0.516

(D) 0.680

(E) 0.950

Question

Beckham Delgado

Mathematics

9 August, 11:46

Many urban zoos are looking at ways to effectively handle animal waste. One zoo has installed a facility that will transform animal waste into electricity. To estimate how many pounds of waste they may have to fuel the new facility they began keeping meticulous records. They discovered that the amount of animal waste they were disposing of daily is approximately Normal with a mean of 348.5 pounds and a standard deviation of 38.2 pounds. Amounts over 350 pounds would generate enough electricity to cover what is needed to for the entire aquarium that day. Approximately what proportion of the days can the zoo expect to obtain enough waste to cover what is needed to run the entire aquarium for the day?

(A) 0.484

(B) 0.499

(C) 0.516

(D) 0.680

(E) 0.950

+1

Answers (1)

Know the Answer?

Beckham Chase · Answer 1

Answer: The correct answer is (A).

Step-by-step explanation:

Let X = the amount of waste produced in a given day. X follows a distribution that is approximately Normal with a mean of 348.5 pounds and a standard deviation of 38.2 pounds.

P (X > 350) = Normalcdf (lower: 350, upper: 1000, mean: 348.5, SD: 38.2) = 0.484.