what is the solution to this system of linear equations? 2x 3y = 3. 7x-3y = 24 a. (2, 7) b. (3, - 21) c. (3, - 1) d. (9, 0)

I) 2X+3Y = 3

II) 7X-3Y = 24

of the equation ii obtain X, 7x-3y = 24⇒ 7X = 24+3Y⇒X = 24 + 3Y / 7

then substitute it value in equation I

2 (24+3y) / 7 + 3Y = 3

48/7+6y/7 + 3y = 3

48+6y+21y = 21

27y = 21-48

27y = - 27

y = - 1

substitute in any equation to obtain x

7x-3y = 24

7x-3 (-1) = 24

7x = 24-3

7x = 21

x = 21/7 = 3

the option C (3,-1)