A newspaper carrier has $4.254.25 in change. he has sevenseven more quarters than dimes but twotwo times as many nickels as quarters. how many coins of each type does he have?

Question

Melvin Jefferson

Mathematics

28 April, 22:13

A newspaper carrier has $4.254.25 in change. he has sevenseven more quarters than dimes but twotwo times as many nickels as quarters. how many coins of each type does he have?

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Answers (1)

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Clay Mcdowell · Answer 1

If the carrier had 7 more dimes, he would have equal numbers of dimes and quarters, and twice as many nickels. His total amount would be

... $4.25 + 0.70 = $4.95.

Each group of 2 nickes, 1 quarter, and 1 dime total $0.45, so the carrier would have $4.95/0.45 = 11 such groups.

The carrier has 11 quarters, 22 nickels, and 4 dimes.