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31 July, 13:21

Group A consists of X students and their total age is 221 and their average age is an integer. When group A is merged with Group B with twice the number of students (the number of students between 30 and 40) average age of B is reduced by 1. What is the original average age of B?

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  1. 31 July, 13:32
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    Mean = sum / count

    Group A

    m = 221 / c

    221 = c x m

    221 = 17 x 13 (as it is a whole number under 20)

    Group B

    m = s / 34

    (221 + x) / 51 = x / 34 - 1

    544 / 34 = 16

    16
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