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Jayce Madden
Mathematics
1 April, 17:17
What are the real zeros of x3 + 4x2 - 9x - 36?
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1 April, 17:36
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X3 + 4x2 - 9x - 36
[x3 + 4x2] - 9 [ x+4]
take x2 common factor from first praket
x2[x+4] - 9 [x+4]
= [x+4] * [x2 - 9]
so the zeros of this equation are - 4, 3, - 3
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