The sum of two numbers is 400. If the first number is decreased by 20% and the second number is decreased by 15%, then the sum would be 68 less. Find the numbers after the decrease.

Let x = the first number

Let y = the second number

So we can set up two equations:

x+y = 400

.8x +.85y = 400-68

Use substitution:

y = 400 - x

.8x + (.85) * (400-x) = 332

.8x + 340 -.85x = 332

8 =.05x

x = 160

So that makes y = 240

We want the decreased values so:

160*.8 = 128

240*.85 = 204

So the answers are 128 and 204