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10 September, 05:35

Factor - 2bk 2 + 6bk - 2b.

A. - 2b (k2 - 3k - 1)

B. - 2b (k2 + 3k + 1)

C. - 2b (k2 - 3k + 1)

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Answers (1)
  1. 10 September, 05:46
    0
    The answer is C. - 2b (k2 - 3k + 1)
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