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9 August, 20:44

How to solve to system y=x^2-2 y=2x+1

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  1. 9 August, 20:52
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    the solutions are (3, 7) and (-1, - 1)

    Step-by-step explanation:

    Insert the " = " symbol between the two equations, obtaining:

    y = x^2 - 2 = y = 2x + 1

    Then x^2 - 2 = 2x + 1, or

    x^2 - 2x - 3 = 0, and this can be factored into (x - 3) (x + 1) = 0.

    Thus, the x values that satisfy this system are {-1, 3}.

    Use y = 2x + 1 to find the corresponding y values:

    y = 2 (-1) + 1 = - 1

    and

    y = 2 (3) + 1 = 7

    Then the solutions are (3, 7) and (-1, - 1)
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