What are the x intercepts of the equation function? Y=x^2+2x-1

(-1 + √2) and (-1 - √2)

Step-by-step explanation:

Given in the question the equation

y = x² + 2x - 1

To find the x-intercept, substitute in 0 for y

0 = x² + 2x - 1

To find value of x use quadratic equation

x = - b ± √b²-4ac / 2a

here a = 1

b = 2

c = - 1

x1 = - 2 + √2²-4 (1) (-1) / 2 (1)

= - 2 + 2√2 / 2

= - 1 + √2

x2 = - 2 - √2²-4 (1) (-1) / 2 (-1)

= - 2 - 2√2 / - 2

= - 1 - √2