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Yesterday, 21:07

What are the zeros of f (x) = x^2-8x+15

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  1. Yesterday, 21:35
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    The zeros are x=5 and x=3

    Step-by-step explanation:

    x^2-8x+15

    To find the zeros, we set the equation equal to zero

    x^2-8x+15 = 0

    Factor the equation

    What 2 numbers multiply to 15 and add to - 8

    -5*-3 = 15

    -5+-3 = - 8

    (x-5) (x-3) = 0

    Using the zero product property

    x-5 = 0 x-3 = 0

    x=5 x=3

    The zeros are x=5 and x=3
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