A bag contains tiles with the letters p-r-o-b-a-b-i-l-i-t-y. tyler chooses a tile without looking and doesn't replace it. he chooses a second tile without looking. what is the probability that he will choose the letter i both times?

Question

Tapia

Mathematics

12 November, 16:30

A bag contains tiles with the letters p-r-o-b-a-b-i-l-i-t-y. tyler chooses a tile without looking and doesn't replace it. he chooses a second tile without looking. what is the probability that he will choose the letter i both times?

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Linda Frederick · Answer 1

Sample space = {p, r, o, b, a, b, i, l, I, t, y} = 11 possible outcomes

1sr event: drawing an I (there are 2 I); P (1st I) = 2/11

2nd event drawing also an i: This is a conditional probability, since one I has already been selected the remaining number of I is now 1, but also the sample space from previously 11 outcome has now 10 outcomes (one letter selected and not replaced)

2nd event : P (also one I) = 1/10

P (selecting one I AND another I) is 2/11 x 1/10

P (selecting one I AND another I) = 2/110 = 0.018