4x^2-16x-5 can be written in vertex form f (x) = a (x-h) ^2+k.

What are the values of a, h, and k.

h=2

a=4

k = - 21

Step-by-step explanation:

your h and k are vertex. h = x coordinate of vertex and k = y

so formula for vertex coordinates is x = - b/2a and y = (4ac-b²) / 4a

your a b c are 4 - 16 and - 5 respectively according to the main equation

your a is concavity which is the same number as the 'a' of the equation