ten people are in a room wearing badges marked 1 through 10. three persons are selected at random and their badge numbers are recorded. what is the probability that the smallest of these badge number is 6?

P=1/12

Step-by-step explanation:

From Exercise we have ten people are in a room wearing badges marked 1 through 10.

For first man we conlude that the probability that is 5/10, that his number at least 6.

For second man we conlude that the probability that is 4/9, that his number at least 6.

For third man we conlude that the probability that is 3/8, that his number at least 6.

Therefore, the probability is

P=5/10 · 4/9 · 3/8 = 1/12

P=1/12