A rubber ball dropped on a hard surface takes a sequence of bounces, each one 2/5 as high as the preceding one. If this ball is dropped from a height of 10 feet, what is the total vertical distance it has traveled at the time when it hits the surface for its fifth bounce?

A. 22 12/25 feet

B. 32 124/125

C. 25 124/125

D. 22 124/125

Question

Ming

Mathematics

29 March, 01:18

A rubber ball dropped on a hard surface takes a sequence of bounces, each one 2/5 as high as the preceding one. If this ball is dropped from a height of 10 feet, what is the total vertical distance it has traveled at the time when it hits the surface for its fifth bounce?

A. 22 12/25 feet

B. 32 124/125

C. 25 124/125

D. 22 124/125

+3

Answers (1)

Know the Answer?

Aurora Cameron · Answer 1

We create first the list of the distances that the ball will travel by multiplying the previous number by 2/5. That is,

10, 4, 8/5, 16/25, 32/125

(1) 10 + 4

(2) 4 + 8/5

(3) 8/5 + 16/25

(4) 16/25 + 32/125

(5) 32/125

Adding all the distances together will give an answer of 22.992 ft or equal to 22 124/125 ft. The answer is letter D.