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Aspen Landry
Mathematics
29 March, 01:15
Given g (x) = x²-3x-6, find (g o g) (-2)
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Cameron Norris
29 March, 01:36
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G (x) = x² - 3x - 6
(g · g) (-2)
g² (-2) = ((-2) ² - 3 (-2) - 6)) ((-2) ² - 3 (-2) - 6))
g² (-2) = (4 + 6 - 6) (4 + 6 - 6)
g² (-2) = (10 - 6) (10 - 6)
g² (-2) = (4) (4)
g² (-2) = 16
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