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16 July, 05:52

Eyjafjallajökull is a Volcano in Ice land. During a recent eruption, the volcano, spewed out copious amounts of ash. One small was ejected from the volcano with an initial velocity of 368ft/sec. The height H, in feet, of our ash projectile is given by the equation H = - 16t + 368t

1. When does the ash projectile reach its maximum height?

2. What is its maximum height?

3. When does the ash projectile return to the ground?

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Answers (1)
  1. 16 July, 06:10
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    1. The maximum height is at H' (t) = 0

    H' (t) = (-16 t² + 368 t) ' = - 32 t + 368

    - 35 t + 368 = 0

    35 t = 368

    t = 368 : 32

    t = 11.5 sec.

    2. H max = - 16 · 11.5² + 368 · 11.5 = - 2,116 + 4.232

    H max = 2,116 ft

    3. It returns to the ground after:

    t = 2 · 11.5 = 23 seconds.
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