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1 January, 03:24

What is the probability that Bo, Colleen, Jeff, and Rohini win the first, second, third, and fourth prizes, respectively, in a drawing if 48 people enter a contest and winning more than one prize is allowed

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  1. 1 January, 03:39
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    1/4669920

    Step-by-step explanation:

    First if all, when repetition is mot allowed, we use Permutation to get the number of possible outcomes as follows;

    P (n, r) = n! / (n - r) !

    Now, the order is important since the first, second, third and fourth prizes are different.

    Thus, we need to define the Permutation.

    We need to select 4 winners of the 48 people.

    Thus, n = 48 and r = 4

    Thus;

    P (48,4) = 48! / (48 - 4) !

    P (48,4) = 4669920

    Now, probability is the number of favourable outcomes divided by number of possible outcomes

    Thus,

    Probability = 1/4669920
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