The length of a rectangle is 3 meters less than twice the width. If the area of the rectangle is 209 square meters, find the dimensions.

Length: 2w - 3

width: w

Area (A) = L x w

209 = (2w - 3) w

209 = 2w² - 3w

0 = 2w² - 3w - 209

0 = (2w + 19) (w - 11)

0 = 2w + 19 0 = w - 11

w = - 19/2 w = 11

Since width cannot be negative, disregard - 19/2

w = 11

Length: 2w - 3 = 2 (11) - 3 = 22 - 3 = 19

Answer: width = 11 meters, length = 19 meters