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24 March, 01:57

Fred is given a rectangular piece of paper. If the length of Fred's

piece of paper is represented by 2x - 6 and the width is represented

by 3x - 5, then the paper has a total area represented by

(1) 5x - 11 (3) 10x - 22

(2) 6x^2 - 28x + 30 (4) 6x^2 - 6x - 11

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Answers (2)
  1. 24 March, 02:06
    0
    It would be length times width, so you would set it up like this: (2x-6) (3x-5).

    Next, you would have to multiply them together, so it would look like this:

    6x^2-10x-18x+30.

    Finally, you combine like terms (-10x and - 18x) to get: 6x^2-28x+30, which is (2).
  2. 24 March, 02:23
    0
    The total area would be length times width, so that would look like, (2x-6) (3x-5)

    If you multiply those out, it would equal (2) 6x²-28x+30
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Home » Mathematics » Fred is given a rectangular piece of paper. If the length of Fred's piece of paper is represented by 2x - 6 and the width is represented by 3x - 5, then the paper has a total area represented by (1) 5x - 11 (3) 10x - 22 (2) 6x^2 - 28x + 30 (4) 6x^2
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