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25 August, 02:06

How do i solve x=y+1 and 3x+2y=8 by substitution

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  1. 25 August, 02:09
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    3 (y+1) + 2y=8

    3y + 3 + 2y = 8

    5y + 3 = 8

    -3 - 3

    5y = 5

    - - - - - -

    5 5

    y=1
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