If (x) = 2e^x-1 + 3, what is f^-1 (x)

f^-1 (x) = 1+ln ((x-3) / 2)

Step-by-step explanation:

hello:

let f (x) = y so : y = 2e^ (x-1) + 3

calculate x : e^ (x-1) = (y-3) / 2

for : y-3 > 0 : x-1 = ln ((y-3) / 2) so : x = 1+ln ((y-3) / 2)

If (x) = 2e^ (x-1) + 3, what is f^-1 (x) = 1+ln ((x-3) / 2)