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5th term in expansion of (x-2) ^7

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  1. 8 May, 01:08
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    560x^3

    Step-by-step explanation:

    The formula is

    (r + 1) th term of (a + x) ^n = nCr a^ (n-r) x^r

    So 5th term = (4 + 1) th term

    = 7C4 x^ (7-4) (-2) ^4

    = 35x^3*16

    = 560x^3
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