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Michelle Mclean
Mathematics
8 May, 00:58
5th term in expansion of (x-2) ^7
+1
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Toby Good
8 May, 01:08
0
560x^3
Step-by-step explanation:
The formula is
(r + 1) th term of (a + x) ^n = nCr a^ (n-r) x^r
So 5th term = (4 + 1) th term
= 7C4 x^ (7-4) (-2) ^4
= 35x^3*16
= 560x^3
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