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19 May, 15:56

A rectangle shape whose length is 4 inches less than twice its width. the area is 30 square inches. whats the dimension

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  1. 19 May, 16:13
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    Using the given information, we can say the following:

    Width (W) = x

    Length (L) = (2x - 4)

    Area of Rectangle = L * W

    Using this, we can formulate an equation for rectangle in question:

    x (2x - 4) = 30

    Expand and move everything to one side:

    2x² - 4x - 30 = 0

    Simplify by dividing everything on both sides by 2:

    x² - 2x - 15 = 0

    Factorise:

    (x + 5) (x - 3) = 0

    Set each factor equal to 0 and solve for x:

    x + 5 = 0

    x = - 5 (a dimension cannot be negative so this is not the solution we want)

    x - 3 = 0

    x = 3 (this is the solution)

    x = W = 3"

    L = 2x - 4

    L = 2 (3) - 4

    L = 2"

    So, the length the rectangle is 2" and the width is 3"
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