F (x) = 2 (x) ^2+5 (x+2) f (2)

f=

-2x^2+y / 10x+20

Step-by-step explanation:

Let's solve for f.

y=2x^2+5 (x+2) f (2)

Step 1: Flip the equation.

10fx+2x^2+20f=y

Step 2: Add - 2x^2 to both sides.

10fx+2x^2+20f+-2x^2=y+-2x^2

10fx+20f=-2x^2+y

Step 3: Factor out variable f.

f (10x+20) = -2x^2+y

Step 4: Divide both sides by 10x+20.

f (10x+20) /

10x+20

=

-2x2+y

10x+20