How many solutions does x^2-8x + 16=0 have and which ones are they

2

Step-by-step explanation:

Given

x² - 8x + 16 = 0

Consider the factors of the constant term ( + 16) which sum to give the coefficient of the x - term ( - 8)

The factors are - 4 and - 4, since

- 4 * - 4 = + 16 and - 4 - 4 = - 8, thus

(x - 4) (x - 4) = 0

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x - 4 = 0 ⇒ x = 4

The solution is x = 4 with multiplicity 2