A contractor can pay his crew at most $425 a day. It costs $80 each day to operate the forklift and $65 a day for each crew member. Write an inequality to represent the contractor's budget for the day.

A. 80x - 65 ≤ 425

B. 80x - 65 ≥ 425

C. 80 + 65x ≤ 425

D. 80 + 65x ≥ 425

Question

Chaya Moyer

Mathematics

6 March, 20:01

A contractor can pay his crew at most $425 a day. It costs $80 each day to operate the forklift and $65 a day for each crew member. Write an inequality to represent the contractor's budget for the day.

A. 80x - 65 ≤ 425

B. 80x - 65 ≥ 425

C. 80 + 65x ≤ 425

D. 80 + 65x ≥ 425

+1

Answers (2)

Know the Answer?

Dodson · Answer 1

the answer is c. 80 + 65x ≤ 425

Orlando Lyons · Answer 2

80 + 65x ≤ 425

Step-by-step explanation:

First of all we know that the 425 must be greater than or equal to the other side, so the symbol to show that would be ≤. We also know that the forklift is a fixed price by the words 'each day'. And the to hire a single crew member would be $65 unless there are more crew workers, which would be multiplied with the 65.

A contractor can pay his crew at most $425 a day. It costs $80 each day to operate the forklift and $65 a day for each crew member. Write an inequality to represent the contractor's budget for the day.A. 80x - 65 ≤ 425B. 80x - 65 ≥ 425C. 80 + 65x ≤ 425D. 80 + 65x ≥ 425

A contractor can pay his crew at most $425 a day. It costs $80 each day to operate the forklift and $65 a day for each crew member. Write an inequality to represent the contractor's budget for the day.

A. 80x - 65 ≤ 425

B. 80x - 65 ≥ 425

C. 80 + 65x ≤ 425

D. 80 + 65x ≥ 425