Ask Question
23 July, 15:03

Which of the following is a polynomial function in standard form with zeros at - 6, 2, and 5?

f (x) = (x + 6) (x - 2) (x - 5)

f (x) = x3 + x2 - 32x - 60

f (x) = x3 - x2 - 32x + 60

f (x) = (x - 6) (x + 2) (x + 5)

+3
Answers (1)
  1. 23 July, 15:32
    0
    Option C is correct.

    Step-by-step explanation:

    We need to find the polynomial function in standard form with zeros at - 6, 2, and 5

    If a is a zero of polynomial then x-a is the factor of polynomial

    So, (x+6) (x-2) (x-5) are factors of polynomial.

    Multiplying these factors to find the standard polynomial function

    (x+6) (x-2) (x-5)

    We need to solve this:

    (x+6) (x^2-5x-2x+10)

    (x+6) (x^2-7x+10)

    x^3-7x^2+10x+6x^2-42x+60

    x^3-7x^2+6x^2+10x-42x+60

    x^3-x^2-32x+60

    So, Option C f (x) = x3 - x2 - 32x + 60 is correct.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Which of the following is a polynomial function in standard form with zeros at - 6, 2, and 5? f (x) = (x + 6) (x - 2) (x - 5) f (x) = x3 + ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers