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5 July, 19:51

Solve 3 over x minus 3 equals the quantity of x over x minus 3, minus three-halves for x and determine if the solution is extraneous or not. x = 3, non-extraneous x = 3, extraneous x = - 3, extraneous x = - 3, non-extraneous

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  1. 5 July, 19:59
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    Multiply both sides by 2 (x-3)

    6=2x-3 x2 + 9x, 3 x2 - 11x+6=0

    3x^2-9x-2x+6=0

    3x (x-3) - 2 (x-3) = 0

    (x-3) (3x-2) = 0 x-3=0 or x=3 is an extraneous root. or 3x-2=0 calculate x.
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