A consumer organization estimates that 35% of the households in a particular community have one television set, 39% have two sets, and 16% have three or more sets. If two independent households are chosen at random, what is the probability that at least one has one or more television sets

Question

Keith Roy

Mathematics

9 December, 12:28

A consumer organization estimates that 35% of the households in a particular community have one television set, 39% have two sets, and 16% have three or more sets. If two independent households are chosen at random, what is the probability that at least one has one or more television sets

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Answers (1)

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Francis Wilkerson · Answer 1

90%

Step-by-step explanation:

Probability of households with one TV = 35% or 0.35

Probability of households with two sets = 39% or 0.39

Probability of households with three or more = 16% or 0.16

The probability of a household with no TV set = 0.10 or 10% (1 - 0.35 - 0.39 - 0.16)

Therefore, the probability of a household with at least one or more sets = 90% (35% + 39% + 16%) or 100% - 10%.

Probability is the chance that something may occur out of many events. To calculate probability, we divide the number of events by the number of possible outcomes.