Suppose P (x) represents the profit on the sale of x Blu-ray discs. If P (1,000) = 5,000 and P' (1,000) = - 3, what do these values tell you about the profit? P (1,000) represents the profit on the sale of Blu-ray discs. P (1,000) = 5,000, so the profit on the sale of Blu-ray discs is $. P' (x) represents the as a function of x. P' (1,000) = - 3, so the profit is decreasing at the rate of $ per additional Blu-ray disc sold.

Question

Ethan Rush

Mathematics

1 October, 00:50

Suppose P (x) represents the profit on the sale of x Blu-ray discs. If P (1,000) = 5,000 and P' (1,000) = - 3, what do these values tell you about the profit? P (1,000) represents the profit on the sale of Blu-ray discs. P (1,000) = 5,000, so the profit on the sale of Blu-ray discs is $. P' (x) represents the as a function of x. P' (1,000) = - 3, so the profit is decreasing at the rate of $ per additional Blu-ray disc sold.

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Averie Bond · Answer 1

Step-by-step explanation:

We are told that P (x) is the profit of saling x blu ray discs. P (1000) is our profit for selling 1000 blu ray discs. So, our profit is 5000. Recall that the derivative P' (x) represents the rate at which the function P (x) is increasing/decreasing (increasing if P' (x) is positive, or decreasing otherwise) by increasing the values of x. In this case P' (1000) = -3, so the profit will decrease - 3 if we increase x in one unit.