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1 October, 00:47

Complete the square to rewrite y = x2 - 6x 16 in vertex form. then state whether the vertex is a maximum or minimum and give its coordinates.

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  1. 1 October, 01:00
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    Actually, you're missing a sign in there. Knowing how completing the square works, I personally know that it has to a - 16, but be careful to post your problems correctly. Set the equation to equal zero, then move the 16 over by adding to both sides to get: x^2 - 6x = 16. Now take half the linear term (the x term), square it, and add that value to both sides to get: x^2 - 6x + 9 = 16 + 9.

    Now simplify both sides by making the left side into the perfect binomial square you intended and add the right: (x-3) ^2 = 25. Move the 25 back over to see that the vertex is (3, - 25)
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