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27 August, 10:02

Write an equation that defines m (x) as a trinomial where m (x) = (3x - 1) (3 - x) + 4x^2 + 19.

Solve for x when m (x) = 0.

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Answers (2)
  1. 27 August, 10:12
    0
    M (x) = (3x - 1) (3 - x) + 4x^2 + 19

    0 = 9x - 3x^2 - 3 + x + 4x^2 + 19

    0 = x^2 + 10x + 16

    now use quadratic formula

    a = 1 b = 10 c = 16

    x = - b + / - √b²-4ac : 2a

    x = - 10 + / - √100 - 4 (16) : 2

    x = - 10 + / - √100-64 : 2

    x = - 10 + / - √36 : 2

    split the equation

    x = - 10 - 6 : 2 and x = - 10 + 6 : 2

    x = - 16 : 2 x = - 4 : 2

    x = - 8 x = - 2

    so the value for x are - 8 and - 2
  2. 27 August, 10:30
    0
    M (x) = (3x - 1) (3 - x) + 4x² + 19

    0 = 3x (3 - x) - 1 (3 - x) + 4x² + 19

    0 = 3x (3) - 3x (x) - 1 (3) + 1 (x) + 4x² + 19

    0 = 9x - 3x² - 3 + x + 4x² + 19

    0 = - 3x² + 4x² + 9x + x - 3 + 19

    0 = x² + 10x + 16

    x = - (10) ± √ ((10) ² - 4 (1) (16))

    2 (1)

    x = - 10 ± √ (100 - 64)

    2

    x = - 10 ± √ (36)

    2

    x = - 10 ± 6

    2

    x = - 5 ± 3

    x = - 5 + 3 U x = - 5 - 3

    x = - 2 U x = - 8
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