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20 October, 17:05

Write a quadratic equation in standard form (with integer coefficients) that has roots: 2 and - 5?

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  1. 20 October, 17:29
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    y = x^2 + 3x-10

    Step-by-step explanation:

    If we know the roots of a quadratic function, we know that

    y = (x - a) (x-b) where a and b are the roots

    y = (x-2) (x--5)

    y = (x-2) (x+5)

    We need to foil this out to get this in standard form of ax^2 + bx+c

    FOIL (x-2) (x+5)

    First x*x: x^2

    outer : 5*x = 5x

    inner: - 2x = - 2x

    last : - 2*5 = - 10

    Add them up

    x^2 + 5x-2x-10

    x^2 + 3x-10
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